4(2y+4)+(3y+1)=

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Solution for 4(2y+4)+(3y+1)= equation:


Simplifying
4(2y + 4) + (3y + 1) = 0

Reorder the terms:
4(4 + 2y) + (3y + 1) = 0
(4 * 4 + 2y * 4) + (3y + 1) = 0
(16 + 8y) + (3y + 1) = 0

Reorder the terms:
16 + 8y + (1 + 3y) = 0

Remove parenthesis around (1 + 3y)
16 + 8y + 1 + 3y = 0

Reorder the terms:
16 + 1 + 8y + 3y = 0

Combine like terms: 16 + 1 = 17
17 + 8y + 3y = 0

Combine like terms: 8y + 3y = 11y
17 + 11y = 0

Solving
17 + 11y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + 11y = 0 + -17

Combine like terms: 17 + -17 = 0
0 + 11y = 0 + -17
11y = 0 + -17

Combine like terms: 0 + -17 = -17
11y = -17

Divide each side by '11'.
y = -1.545454545

Simplifying
y = -1.545454545

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