4(2y+3)=2(5y-2)+6

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Solution for 4(2y+3)=2(5y-2)+6 equation: 



4(2y+3)=2(5y-2)+6

We move all terms to the left:

4(2y+3)-(2(5y-2)+6)=0

We multiply parentheses

8y-(2(5y-2)+6)+12=0



We calculate terms in parentheses: -(2(5y-2)+6), so:

2(5y-2)+6

We multiply parentheses

10y-4+6

We add all the numbers together, and all the variables

10y+2

Back to the equation:

-(10y+2)



We get rid of parentheses

8y-10y-2+12=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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