4(2y+3)-2y=-(3y-1)+29

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Solution for 4(2y+3)-2y=-(3y-1)+29 equation: 



4(2y+3)-2y=-(3y-1)+29

We move all terms to the left:

4(2y+3)-2y-(-(3y-1)+29)=0

We add all the numbers together, and all the variables

-2y+4(2y+3)-(-(3y-1)+29)=0

We multiply parentheses

-2y+8y-(-(3y-1)+29)+12=0



We calculate terms in parentheses: -(-(3y-1)+29), so:

-(3y-1)+29

We get rid of parentheses

-3y+1+29

We add all the numbers together, and all the variables

-3y+30

Back to the equation:

-(-3y+30)



We add all the numbers together, and all the variables

6y-(-3y+30)+12=0

We get rid of parentheses

6y+3y-30+12=0

We add all the numbers together, and all the variables

9y-18=0

We move all terms containing y to the left, all other terms to the right

9y=18

y=18/9

y=2

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