4(2y+1)=2(y-13)-4y

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Solution for 4(2y+1)=2(y-13)-4y equation: 



4(2y+1)=2(y-13)-4y

We move all terms to the left:

4(2y+1)-(2(y-13)-4y)=0

We multiply parentheses

8y-(2(y-13)-4y)+4=0



We calculate terms in parentheses: -(2(y-13)-4y), so:

2(y-13)-4y

We add all the numbers together, and all the variables

-4y+2(y-13)

We multiply parentheses

-4y+2y-26

We add all the numbers together, and all the variables

-2y-26

Back to the equation:

-(-2y-26)



We get rid of parentheses

8y+2y+26+4=0

We add all the numbers together, and all the variables

10y+30=0

We move all terms containing y to the left, all other terms to the right

10y=-30

y=-30/10

y=-3

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