4(2y+1)-(3+y)=7

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Solution for 4(2y+1)-(3+y)=7 equation: 



4(2y+1)-(3+y)=7

We move all terms to the left:

4(2y+1)-(3+y)-(7)=0

We add all the numbers together, and all the variables

4(2y+1)-(y+3)-7=0

We multiply parentheses

8y-(y+3)+4-7=0

We get rid of parentheses

8y-y-3+4-7=0

We add all the numbers together, and all the variables

7y-6=0

We move all terms containing y to the left, all other terms to the right

7y=6

y=6/7

y=6/7

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