4(2x2)=3x+18

Solution for 4(2x2)=3x+18 equation:

4(2x^2)=3x+18

We move all terms to the left:

4(2x^2)-(3x+18)=0

We get rid of parentheses

42x^2-3x-18=0

a = 42; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·42·(-18)
Δ = 3033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3033}=\sqrt{9*337}=\sqrt{9}*\sqrt{337}=3\sqrt{337}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{337}}{2*42}=\frac{3-3\sqrt{337}}{84}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{337}}{2*42}=\frac{3+3\sqrt{337}}{84}
$