4(2x-8)-4=4(x-5)+12

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Solution for 4(2x-8)-4=4(x-5)+12 equation: 



4(2x-8)-4=4(x-5)+12

We move all terms to the left:

4(2x-8)-4-(4(x-5)+12)=0

We multiply parentheses

8x-(4(x-5)+12)-32-4=0



We calculate terms in parentheses: -(4(x-5)+12), so:

4(x-5)+12

We multiply parentheses

4x-20+12

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

8x-(4x-8)-36=0

We get rid of parentheses

8x-4x+8-36=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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