4(2x-7)-8=4(x-4)+4

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Solution for 4(2x-7)-8=4(x-4)+4 equation: 



4(2x-7)-8=4(x-4)+4

We move all terms to the left:

4(2x-7)-8-(4(x-4)+4)=0

We multiply parentheses

8x-(4(x-4)+4)-28-8=0



We calculate terms in parentheses: -(4(x-4)+4), so:

4(x-4)+4

We multiply parentheses

4x-16+4

We add all the numbers together, and all the variables

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

8x-(4x-12)-36=0

We get rid of parentheses

8x-4x+12-36=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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