4(2x-7)-8=10-2(4x+7)

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Solution for 4(2x-7)-8=10-2(4x+7) equation: 



4(2x-7)-8=10-2(4x+7)

We move all terms to the left:

4(2x-7)-8-(10-2(4x+7))=0

We multiply parentheses

8x-(10-2(4x+7))-28-8=0



We calculate terms in parentheses: -(10-2(4x+7)), so:

10-2(4x+7)

determiningTheFunctionDomain
-2(4x+7)+10

We multiply parentheses

-8x-14+10

We add all the numbers together, and all the variables

-8x-4

Back to the equation:

-(-8x-4)



We add all the numbers together, and all the variables

8x-(-8x-4)-36=0

We get rid of parentheses

8x+8x+4-36=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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