4(2x-7)-2=4(x-4)+18

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Solution for 4(2x-7)-2=4(x-4)+18 equation: 



4(2x-7)-2=4(x-4)+18

We move all terms to the left:

4(2x-7)-2-(4(x-4)+18)=0

We multiply parentheses

8x-(4(x-4)+18)-28-2=0



We calculate terms in parentheses: -(4(x-4)+18), so:

4(x-4)+18

We multiply parentheses

4x-16+18

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

8x-(4x+2)-30=0

We get rid of parentheses

8x-4x-2-30=0

We add all the numbers together, and all the variables

4x-32=0

We move all terms containing x to the left, all other terms to the right

4x=32

x=32/4

x=8

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