4(2x-5)=3(4-2x)

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Solution for 4(2x-5)=3(4-2x) equation: 



4(2x-5)=3(4-2x)

We move all terms to the left:

4(2x-5)-(3(4-2x))=0

We add all the numbers together, and all the variables

4(2x-5)-(3(-2x+4))=0

We multiply parentheses

8x-(3(-2x+4))-20=0



We calculate terms in parentheses: -(3(-2x+4)), so:

3(-2x+4)

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

8x+6x-12-20=0

We add all the numbers together, and all the variables

14x-32=0

We move all terms containing x to the left, all other terms to the right

14x=32

x=32/14

x=2+2/7

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