4(2x-5)-x=6x-2(x-3)+1

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Solution for 4(2x-5)-x=6x-2(x-3)+1 equation: 



4(2x-5)-x=6x-2(x-3)+1

We move all terms to the left:

4(2x-5)-x-(6x-2(x-3)+1)=0

We add all the numbers together, and all the variables

-1x+4(2x-5)-(6x-2(x-3)+1)=0

We multiply parentheses

-1x+8x-(6x-2(x-3)+1)-20=0



We calculate terms in parentheses: -(6x-2(x-3)+1), so:

6x-2(x-3)+1

We multiply parentheses

6x-2x+6+1

We add all the numbers together, and all the variables

4x+7

Back to the equation:

-(4x+7)



We add all the numbers together, and all the variables

7x-(4x+7)-20=0

We get rid of parentheses

7x-4x-7-20=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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