4(2x-5)-8=-5x+4(-5-7x)

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Solution for 4(2x-5)-8=-5x+4(-5-7x) equation: 



4(2x-5)-8=-5x+4(-5-7x)

We move all terms to the left:

4(2x-5)-8-(-5x+4(-5-7x))=0

We add all the numbers together, and all the variables

4(2x-5)-(-5x+4(-7x-5))-8=0

We multiply parentheses

8x-(-5x+4(-7x-5))-20-8=0



We calculate terms in parentheses: -(-5x+4(-7x-5)), so:

-5x+4(-7x-5)

We multiply parentheses

-5x-28x-20

We add all the numbers together, and all the variables

-33x-20

Back to the equation:

-(-33x-20)



We add all the numbers together, and all the variables

8x-(-33x-20)-28=0

We get rid of parentheses

8x+33x+20-28=0

We add all the numbers together, and all the variables

41x-8=0

We move all terms containing x to the left, all other terms to the right

41x=8

x=8/41

x=8/41

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