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4(2x-5)-2(4x-1)=7(3x+3)-2(x-2)
We move all terms to the left:
4(2x-5)-2(4x-1)-(7(3x+3)-2(x-2))=0
We multiply parentheses
8x-8x-(7(3x+3)-2(x-2))-20+2=0
We calculate terms in parentheses: -(7(3x+3)-2(x-2)), so:We add all the numbers together, and all the variables
7(3x+3)-2(x-2)
We multiply parentheses
21x-2x+21+4
We add all the numbers together, and all the variables
19x+25
Back to the equation:
-(19x+25)
-(19x+25)-18=0
We get rid of parentheses
-19x-25-18=0
We add all the numbers together, and all the variables
-19x-43=0
We move all terms containing x to the left, all other terms to the right
-19x=43
x=43/-19
x=-2+5/19
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