4(2x-5)+3(3x-8)=41

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Solution for 4(2x-5)+3(3x-8)=41 equation:


Simplifying
4(2x + -5) + 3(3x + -8) = 41

Reorder the terms:
4(-5 + 2x) + 3(3x + -8) = 41
(-5 * 4 + 2x * 4) + 3(3x + -8) = 41
(-20 + 8x) + 3(3x + -8) = 41

Reorder the terms:
-20 + 8x + 3(-8 + 3x) = 41
-20 + 8x + (-8 * 3 + 3x * 3) = 41
-20 + 8x + (-24 + 9x) = 41

Reorder the terms:
-20 + -24 + 8x + 9x = 41

Combine like terms: -20 + -24 = -44
-44 + 8x + 9x = 41

Combine like terms: 8x + 9x = 17x
-44 + 17x = 41

Solving
-44 + 17x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '44' to each side of the equation.
-44 + 44 + 17x = 41 + 44

Combine like terms: -44 + 44 = 0
0 + 17x = 41 + 44
17x = 41 + 44

Combine like terms: 41 + 44 = 85
17x = 85

Divide each side by '17'.
x = 5

Simplifying
x = 5

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