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4(2x-4)=5(4x-3)
We move all terms to the left:
4(2x-4)-(5(4x-3))=0
We multiply parentheses
8x-(5(4x-3))-16=0
We calculate terms in parentheses: -(5(4x-3)), so:We get rid of parentheses
5(4x-3)
We multiply parentheses
20x-15
Back to the equation:
-(20x-15)
8x-20x+15-16=0
We add all the numbers together, and all the variables
-12x-1=0
We move all terms containing x to the left, all other terms to the right
-12x=1
x=1/-12
x=-1/12
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