4(2x-4)-5=4(x-4)+23

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Solution for 4(2x-4)-5=4(x-4)+23 equation: 



4(2x-4)-5=4(x-4)+23

We move all terms to the left:

4(2x-4)-5-(4(x-4)+23)=0

We multiply parentheses

8x-(4(x-4)+23)-16-5=0



We calculate terms in parentheses: -(4(x-4)+23), so:

4(x-4)+23

We multiply parentheses

4x-16+23

We add all the numbers together, and all the variables

4x+7

Back to the equation:

-(4x+7)



We add all the numbers together, and all the variables

8x-(4x+7)-21=0

We get rid of parentheses

8x-4x-7-21=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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