4(2x-3)=8(x-3)+12

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Solution for 4(2x-3)=8(x-3)+12 equation: 



4(2x-3)=8(x-3)+12

We move all terms to the left:

4(2x-3)-(8(x-3)+12)=0

We multiply parentheses

8x-(8(x-3)+12)-12=0



We calculate terms in parentheses: -(8(x-3)+12), so:

8(x-3)+12

We multiply parentheses

8x-24+12

We add all the numbers together, and all the variables

8x-12

Back to the equation:

-(8x-12)



We get rid of parentheses

8x-8x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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