4(2x-3)=5(x-1)+8

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Solution for 4(2x-3)=5(x-1)+8 equation: 



4(2x-3)=5(x-1)+8

We move all terms to the left:

4(2x-3)-(5(x-1)+8)=0

We multiply parentheses

8x-(5(x-1)+8)-12=0



We calculate terms in parentheses: -(5(x-1)+8), so:

5(x-1)+8

We multiply parentheses

5x-5+8

We add all the numbers together, and all the variables

5x+3

Back to the equation:

-(5x+3)



We get rid of parentheses

8x-5x-3-12=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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