4(2x-3)=3x+28

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Solution for 4(2x-3)=3x+28 equation: 



4(2x-3)=3x+28

We move all terms to the left:

4(2x-3)-(3x+28)=0

We multiply parentheses

8x-(3x+28)-12=0

We get rid of parentheses

8x-3x-28-12=0

We add all the numbers together, and all the variables

5x-40=0

We move all terms containing x to the left, all other terms to the right

5x=40

x=40/5

x=8

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