4(2x-3)=3(x-5)+(7x-2)

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Solution for 4(2x-3)=3(x-5)+(7x-2) equation: 



4(2x-3)=3(x-5)+(7x-2)

We move all terms to the left:

4(2x-3)-(3(x-5)+(7x-2))=0

We multiply parentheses

8x-(3(x-5)+(7x-2))-12=0



We calculate terms in parentheses: -(3(x-5)+(7x-2)), so:

3(x-5)+(7x-2)

We multiply parentheses

3x+(7x-2)-15

We get rid of parentheses

3x+7x-2-15

We add all the numbers together, and all the variables

10x-17

Back to the equation:

-(10x-17)



We get rid of parentheses

8x-10x+17-12=0

We add all the numbers together, and all the variables

-2x+5=0

We move all terms containing x to the left, all other terms to the right

-2x=-5

x=-5/-2

x=2+1/2

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