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4(2x-3)=3(2x-2)
We move all terms to the left:
4(2x-3)-(3(2x-2))=0
We multiply parentheses
8x-(3(2x-2))-12=0
We calculate terms in parentheses: -(3(2x-2)), so:We get rid of parentheses
3(2x-2)
We multiply parentheses
6x-6
Back to the equation:
-(6x-6)
8x-6x+6-12=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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