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4(2x-3)=2(x-3)
We move all terms to the left:
4(2x-3)-(2(x-3))=0
We multiply parentheses
8x-(2(x-3))-12=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
8x-2x+6-12=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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