4(2x-3)-5(x-4)=x+1-(3x+2)

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Solution for 4(2x-3)-5(x-4)=x+1-(3x+2) equation: 



4(2x-3)-5(x-4)=x+1-(3x+2)

We move all terms to the left:

4(2x-3)-5(x-4)-(x+1-(3x+2))=0

We multiply parentheses

8x-5x-(x+1-(3x+2))-12+20=0



We calculate terms in parentheses: -(x+1-(3x+2)), so:

x+1-(3x+2)

determiningTheFunctionDomain
x-(3x+2)+1

We get rid of parentheses

x-3x-2+1

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We add all the numbers together, and all the variables

3x-(-2x-1)+8=0

We get rid of parentheses

3x+2x+1+8=0

We add all the numbers together, and all the variables

5x+9=0

We move all terms containing x to the left, all other terms to the right

5x=-9

x=-9/5

x=-1+4/5

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