4(2x-3)-3x=13+5(x-3x)

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Solution for 4(2x-3)-3x=13+5(x-3x) equation: 



4(2x-3)-3x=13+5(x-3x)

We move all terms to the left:

4(2x-3)-3x-(13+5(x-3x))=0

We add all the numbers together, and all the variables

4(2x-3)-3x-(13+5(-2x))=0

We add all the numbers together, and all the variables

-3x+4(2x-3)-(13+5(-2x))=0

We multiply parentheses

-3x+8x-(13+5(-2x))-12=0



We calculate terms in parentheses: -(13+5(-2x)), so:

13+5(-2x)

determiningTheFunctionDomain
5(-2x)+13

We multiply parentheses

-10x+13

Back to the equation:

-(-10x+13)



We add all the numbers together, and all the variables

5x-(-10x+13)-12=0

We get rid of parentheses

5x+10x-13-12=0

We add all the numbers together, and all the variables

15x-25=0

We move all terms containing x to the left, all other terms to the right

15x=25

x=25/15

x=1+2/3

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