4(2x-3)-3(x-)+7x=6

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Solution for 4(2x-3)-3(x-)+7x=6 equation: 



4(2x-3)-3(x-)+7x=6

We move all terms to the left:

4(2x-3)-3(x-)+7x-(6)=0

We add all the numbers together, and all the variables

4(2x-3)-3(+x)+7x-6=0

We add all the numbers together, and all the variables

7x+4(2x-3)-3(+x)-6=0

We multiply parentheses

7x+8x-3x-12-6=0

We add all the numbers together, and all the variables

12x-18=0

We move all terms containing x to the left, all other terms to the right

12x=18

x=18/12

x=1+1/2

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