4(2x-3)+8(x-4)=(2x+6)

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Solution for 4(2x-3)+8(x-4)=(2x+6) equation: 



4(2x-3)+8(x-4)=(2x+6)

We move all terms to the left:

4(2x-3)+8(x-4)-((2x+6))=0

We multiply parentheses

8x+8x-((2x+6))-12-32=0



We calculate terms in parentheses: -((2x+6)), so:

(2x+6)

We get rid of parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

16x-(2x+6)-44=0

We get rid of parentheses

16x-2x-6-44=0

We add all the numbers together, and all the variables

14x-50=0

We move all terms containing x to the left, all other terms to the right

14x=50

x=50/14

x=3+4/7

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