4(2x-3)+10=5(2x-10)+6x

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Solution for 4(2x-3)+10=5(2x-10)+6x equation: 



4(2x-3)+10=5(2x-10)+6x

We move all terms to the left:

4(2x-3)+10-(5(2x-10)+6x)=0

We multiply parentheses

8x-(5(2x-10)+6x)-12+10=0



We calculate terms in parentheses: -(5(2x-10)+6x), so:

5(2x-10)+6x

We add all the numbers together, and all the variables

6x+5(2x-10)

We multiply parentheses

6x+10x-50

We add all the numbers together, and all the variables

16x-50

Back to the equation:

-(16x-50)



We add all the numbers together, and all the variables

8x-(16x-50)-2=0

We get rid of parentheses

8x-16x+50-2=0

We add all the numbers together, and all the variables

-8x+48=0

We move all terms containing x to the left, all other terms to the right

-8x=-48

x=-48/-8

x=+6

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