4(2x-3)+(3x-4)=14

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Solution for 4(2x-3)+(3x-4)=14 equation: 



4(2x-3)+(3x-4)=14

We move all terms to the left:

4(2x-3)+(3x-4)-(14)=0

We multiply parentheses

8x+(3x-4)-12-14=0

We get rid of parentheses

8x+3x-4-12-14=0

We add all the numbers together, and all the variables

11x-30=0

We move all terms containing x to the left, all other terms to the right

11x=30

x=30/11

x=2+8/11

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