4(2x-20)=3x-(x+5)

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Solution for 4(2x-20)=3x-(x+5) equation: 



4(2x-20)=3x-(x+5)

We move all terms to the left:

4(2x-20)-(3x-(x+5))=0

We multiply parentheses

8x-(3x-(x+5))-80=0



We calculate terms in parentheses: -(3x-(x+5)), so:

3x-(x+5)

We get rid of parentheses

3x-x-5

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

8x-2x+5-80=0

We add all the numbers together, and all the variables

6x-75=0

We move all terms containing x to the left, all other terms to the right

6x=75

x=75/6

x=12+1/2

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