4(2x-2)-3=4(x-5)+25

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Solution for 4(2x-2)-3=4(x-5)+25 equation:



4(2x-2)-3=4(x-5)+25
We move all terms to the left:
4(2x-2)-3-(4(x-5)+25)=0
We multiply parentheses
8x-(4(x-5)+25)-8-3=0
We calculate terms in parentheses: -(4(x-5)+25), so:
4(x-5)+25
We multiply parentheses
4x-20+25
We add all the numbers together, and all the variables
4x+5
Back to the equation:
-(4x+5)
We add all the numbers together, and all the variables
8x-(4x+5)-11=0
We get rid of parentheses
8x-4x-5-11=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4

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