4(2x-2)+3(x-4)=57

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Solution for 4(2x-2)+3(x-4)=57 equation: 



4(2x-2)+3(x-4)=57

We move all terms to the left:

4(2x-2)+3(x-4)-(57)=0

We multiply parentheses

8x+3x-8-12-57=0

We add all the numbers together, and all the variables

11x-77=0

We move all terms containing x to the left, all other terms to the right

11x=77

x=77/11

x=7

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