4(2x-2)+2(3x-2)=12

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Solution for 4(2x-2)+2(3x-2)=12 equation: 



4(2x-2)+2(3x-2)=12

We move all terms to the left:

4(2x-2)+2(3x-2)-(12)=0

We multiply parentheses

8x+6x-8-4-12=0

We add all the numbers together, and all the variables

14x-24=0

We move all terms containing x to the left, all other terms to the right

14x=24

x=24/14

x=1+5/7

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