4(2x-10)+12-4x=40

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Solution for 4(2x-10)+12-4x=40 equation: 



4(2x-10)+12-4x=40

We move all terms to the left:

4(2x-10)+12-4x-(40)=0

We add all the numbers together, and all the variables

-4x+4(2x-10)-28=0

We multiply parentheses

-4x+8x-40-28=0

We add all the numbers together, and all the variables

4x-68=0

We move all terms containing x to the left, all other terms to the right

4x=68

x=68/4

x=17

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