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4(2x-1)+3=2(3x-2)+15
We move all terms to the left:
4(2x-1)+3-(2(3x-2)+15)=0
We multiply parentheses
8x-(2(3x-2)+15)-4+3=0
We calculate terms in parentheses: -(2(3x-2)+15), so:We add all the numbers together, and all the variables
2(3x-2)+15
We multiply parentheses
6x-4+15
We add all the numbers together, and all the variables
6x+11
Back to the equation:
-(6x+11)
8x-(6x+11)-1=0
We get rid of parentheses
8x-6x-11-1=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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