4(2x-)+5=-3(2x+3)-125

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Solution for 4(2x-)+5=-3(2x+3)-125 equation: 



4(2x-)+5=-3(2x+3)-125

We move all terms to the left:

4(2x-)+5-(-3(2x+3)-125)=0

We add all the numbers together, and all the variables

4(+2x)-(-3(2x+3)-125)+5=0

We multiply parentheses

8x-(-3(2x+3)-125)+5=0



We calculate terms in parentheses: -(-3(2x+3)-125), so:

-3(2x+3)-125

We multiply parentheses

-6x-9-125

We add all the numbers together, and all the variables

-6x-134

Back to the equation:

-(-6x-134)



We get rid of parentheses

8x+6x+134+5=0

We add all the numbers together, and all the variables

14x+139=0

We move all terms containing x to the left, all other terms to the right

14x=-139

x=-139/14

x=-9+13/14

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