4(2x+5)=32(x-4)

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Solution for 4(2x+5)=32(x-4) equation: 



4(2x+5)=32(x-4)

We move all terms to the left:

4(2x+5)-(32(x-4))=0

We multiply parentheses

8x-(32(x-4))+20=0



We calculate terms in parentheses: -(32(x-4)), so:

32(x-4)

We multiply parentheses

32x-128

Back to the equation:

-(32x-128)



We get rid of parentheses

8x-32x+128+20=0

We add all the numbers together, and all the variables

-24x+148=0

We move all terms containing x to the left, all other terms to the right

-24x=-148

x=-148/-24

x=6+1/6

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