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4(2x+5)=3(x-3)
We move all terms to the left:
4(2x+5)-(3(x-3))=0
We multiply parentheses
8x-(3(x-3))+20=0
We calculate terms in parentheses: -(3(x-3)), so:We get rid of parentheses
3(x-3)
We multiply parentheses
3x-9
Back to the equation:
-(3x-9)
8x-3x+9+20=0
We add all the numbers together, and all the variables
5x+29=0
We move all terms containing x to the left, all other terms to the right
5x=-29
x=-29/5
x=-5+4/5
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