4(2x+5)=-28+32

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Solution for 4(2x+5)=-28+32 equation: 



4(2x+5)=-28+32

We move all terms to the left:

4(2x+5)-(-28+32)=0

We add all the numbers together, and all the variables

4(2x+5)-4=0

We multiply parentheses

8x+20-4=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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