4(2x+5)-3(x-2)=16

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Solution for 4(2x+5)-3(x-2)=16 equation: 



4(2x+5)-3(x-2)=16

We move all terms to the left:

4(2x+5)-3(x-2)-(16)=0

We multiply parentheses

8x-3x+20+6-16=0

We add all the numbers together, and all the variables

5x+10=0

We move all terms containing x to the left, all other terms to the right

5x=-10

x=-10/5

x=-2

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