4(2x+5)+6=32

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Solution for 4(2x+5)+6=32 equation: 



4(2x+5)+6=32

We move all terms to the left:

4(2x+5)+6-(32)=0

We add all the numbers together, and all the variables

4(2x+5)-26=0

We multiply parentheses

8x+20-26=0

We add all the numbers together, and all the variables

8x-6=0

We move all terms containing x to the left, all other terms to the right

8x=6

x=6/8

x=3/4

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