If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4(2x+4)=2(2x+4)
We move all terms to the left:
4(2x+4)-(2(2x+4))=0
We multiply parentheses
8x-(2(2x+4))+16=0
We calculate terms in parentheses: -(2(2x+4)), so:We get rid of parentheses
2(2x+4)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
8x-4x-8+16=0
We add all the numbers together, and all the variables
4x+8=0
We move all terms containing x to the left, all other terms to the right
4x=-8
x=-8/4
x=-2
| 4(2x+4)=2(2+4) | | (3x-5)+(2+3x)=0 | | 6.7g+4=3.7g+19 | | 14x+90=8x+90 | | 5(12x+2)=3(5x+3) | | 14x-90=22x+90 | | -6x+3(2x+8)=12 | | -6x+6x+24=12 | | 10+3c=6c-11 | | 7h+2=63 | | 9x=15-12x | | x-2=5x+4 | | 10x-5=12x+3 | | -4a+16a+-14a=10 | | 5h-10=h+6 | | 3(2x-5)-31=14 | | (x+7)/3=x/5 | | 4x=210-2x | | 12(x-24)=24(x-27) | | -6q+14q+-6q=20 | | 5n+7+n=3n-2+2(2n+1 | | 3x-55=233-x | | 27=9^-x+1 | | 2a+8=6a-8 | | 3z=6z-6 | | 8+3e÷19=2 | | x+2x+((x+2x)-20)=196 | | 10m-9=9+7m | | v5−6=3 | | z^2-12z+30=0 | | 7y-32=6y+18 | | 5x²+8x-13=0 |