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4(2x+4)-3(x-1)=2(4x-2)+5x
We move all terms to the left:
4(2x+4)-3(x-1)-(2(4x-2)+5x)=0
We multiply parentheses
8x-3x-(2(4x-2)+5x)+16+3=0
We calculate terms in parentheses: -(2(4x-2)+5x), so:We add all the numbers together, and all the variables
2(4x-2)+5x
We add all the numbers together, and all the variables
5x+2(4x-2)
We multiply parentheses
5x+8x-4
We add all the numbers together, and all the variables
13x-4
Back to the equation:
-(13x-4)
5x-(13x-4)+19=0
We get rid of parentheses
5x-13x+4+19=0
We add all the numbers together, and all the variables
-8x+23=0
We move all terms containing x to the left, all other terms to the right
-8x=-23
x=-23/-8
x=2+7/8
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