4(2x+3)=7(4x-4)

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Solution for 4(2x+3)=7(4x-4) equation: 



4(2x+3)=7(4x-4)

We move all terms to the left:

4(2x+3)-(7(4x-4))=0

We multiply parentheses

8x-(7(4x-4))+12=0



We calculate terms in parentheses: -(7(4x-4)), so:

7(4x-4)

We multiply parentheses

28x-28

Back to the equation:

-(28x-28)



We get rid of parentheses

8x-28x+28+12=0

We add all the numbers together, and all the variables

-20x+40=0

We move all terms containing x to the left, all other terms to the right

-20x=-40

x=-40/-20

x=+2

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