4(2x+3)=16x+6-8x+6

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Solution for 4(2x+3)=16x+6-8x+6 equation:



4(2x+3)=16x+6-8x+6
We move all terms to the left:
4(2x+3)-(16x+6-8x+6)=0
We add all the numbers together, and all the variables
4(2x+3)-(8x+12)=0
We multiply parentheses
8x-(8x+12)+12=0
We get rid of parentheses
8x-8x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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