4(2x+3)=-4(3x-5)+3x

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Solution for 4(2x+3)=-4(3x-5)+3x equation: 



4(2x+3)=-4(3x-5)+3x

We move all terms to the left:

4(2x+3)-(-4(3x-5)+3x)=0

We multiply parentheses

8x-(-4(3x-5)+3x)+12=0



We calculate terms in parentheses: -(-4(3x-5)+3x), so:

-4(3x-5)+3x

We add all the numbers together, and all the variables

3x-4(3x-5)

We multiply parentheses

3x-12x+20

We add all the numbers together, and all the variables

-9x+20

Back to the equation:

-(-9x+20)



We get rid of parentheses

8x+9x-20+12=0

We add all the numbers together, and all the variables

17x-8=0

We move all terms containing x to the left, all other terms to the right

17x=8

x=8/17

x=8/17

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