4(2x+3)=(2x-2)+2(3x+7)

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Solution for 4(2x+3)=(2x-2)+2(3x+7) equation: 



4(2x+3)=(2x-2)+2(3x+7)

We move all terms to the left:

4(2x+3)-((2x-2)+2(3x+7))=0

We multiply parentheses

8x-((2x-2)+2(3x+7))+12=0



We calculate terms in parentheses: -((2x-2)+2(3x+7)), so:

(2x-2)+2(3x+7)

We multiply parentheses

(2x-2)+6x+14

We get rid of parentheses

2x+6x-2+14

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

8x-8x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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