4(2x+3)-6x-5=12+5(x-3)+8

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Solution for 4(2x+3)-6x-5=12+5(x-3)+8 equation: 



4(2x+3)-6x-5=12+5(x-3)+8

We move all terms to the left:

4(2x+3)-6x-5-(12+5(x-3)+8)=0

We add all the numbers together, and all the variables

-6x+4(2x+3)-(12+5(x-3)+8)-5=0

We multiply parentheses

-6x+8x-(12+5(x-3)+8)+12-5=0



We calculate terms in parentheses: -(12+5(x-3)+8), so:

12+5(x-3)+8

determiningTheFunctionDomain
5(x-3)+12+8

We add all the numbers together, and all the variables

5(x-3)+20

We multiply parentheses

5x-15+20

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

2x-(5x+5)+7=0

We get rid of parentheses

2x-5x-5+7=0

We add all the numbers together, and all the variables

-3x+2=0

We move all terms containing x to the left, all other terms to the right

-3x=-2

x=-2/-3

x=2/3

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