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4(2x+3)-3x=2(x+1)-1
We move all terms to the left:
4(2x+3)-3x-(2(x+1)-1)=0
We add all the numbers together, and all the variables
-3x+4(2x+3)-(2(x+1)-1)=0
We multiply parentheses
-3x+8x-(2(x+1)-1)+12=0
We calculate terms in parentheses: -(2(x+1)-1), so:We add all the numbers together, and all the variables
2(x+1)-1
We multiply parentheses
2x+2-1
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
5x-(2x+1)+12=0
We get rid of parentheses
5x-2x-1+12=0
We add all the numbers together, and all the variables
3x+11=0
We move all terms containing x to the left, all other terms to the right
3x=-11
x=-11/3
x=-3+2/3
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