4(2x+3)+2(3x-4)=3x-x+40

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Solution for 4(2x+3)+2(3x-4)=3x-x+40 equation: 



4(2x+3)+2(3x-4)=3x-x+40

We move all terms to the left:

4(2x+3)+2(3x-4)-(3x-x+40)=0

We add all the numbers together, and all the variables

4(2x+3)+2(3x-4)-(2x+40)=0

We multiply parentheses

8x+6x-(2x+40)+12-8=0

We get rid of parentheses

8x+6x-2x-40+12-8=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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